If work done is stretching a wire by 1mm
Web11 nov. 2024 · Now, dividing both sides by volume of the wire we get energy stored in unit volume of wire. U V = 1 2 F l A L = ½ x Stress x Strain = ½ x Y x (Strain)². U V = 1 2 Y ( … Web26 feb. 2012 · Work done in stretching a wire Consider a electric wire is under the force F This force stretches the wire through a small elongation x. Let length of wire = L Force F produce an extension = x From the figure Work done on the wire during stretching = Area covered on the x -axis = Average force × extension Work done, W = Energy stored
If work done is stretching a wire by 1mm
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Web18 feb. 2024 · Find the work done in stretching a wire of length 2 m and of sectional area 1 mm² through 1 mm if Young’s modulus of the material of the wire is 2 × 10 11 N/m². … WebIf a metal wire is 4m long and a force of 5000N causes it to stretch by 1mm, ... Match. Created by. Erica_Wangelin. Terms in this set (15) 0.00025. If a metal wire is 4m long …
Web31 okt. 2024 · Explanation: In stretching a wire work is done against internal restoring forces. This work is stored as elastic potential energy or strain energy. If a force F acts along the length L of the wire or cross section A and stretches it by x then: Young′sModulus (Y)=StressStrain=F/Ax/L=FLAx⇒F=YALx.
WebIf the work done in stretching a wire by 1 mm is 2J, then work necessary for stretching another wire of same material ... mm is A. 4 B. 8 C. 2 D. 16 Web29 nov. 2024 · (a) A wire 4 m ling and 0.3 mm in diameter is stretched by a force of 100 N. If extension in the wire is 0.3 mm, calculate the potential energy stored in the wire. (b) Find the work done in stretching a wire of cross-section 1 mm2 and length 2 m through 0.1 mm Young's modulus for the material of wire is 2.0 x 1011 N/m2. elasticity jee jee mains
Web29 apr. 2024 · Click here 👆 to get an answer to your question ️ If 3×10-3j of work is done in stretching a wire through 1mm the workdone in stretching it through 3mm is. …
Web1 apr. 2024 · Now coming on the question, we are asked about the work done when a wire is stretched, Formula for the work done is W = 1 2 ×F× Δ l ….. (1) , where F is the force … fitbit record blood pressureWebIf the work done in stretching a wire by 1 mm is 2 J, the work necessary for stretching another wire of same material but with double radius of cross-section and half the length … can garden hoses be left outside in winterWebIf the work done in stretching a wire by $$1mm$$ is $$2J$$, the work necessary for stretching another wire of same material but with double radius of cross-section and … fitbit recordingWeb31 dec. 2024 · A wire of cross-sectional area A is stretched horizontally between two clamps loaded at a distance 2 l metres from each other. A weight w kg is suspended from the … fitbit redditWeb19 apr. 2024 · Correct option: (B) 2 × 10–2 J Explanation: given : L = 0.5 m A = 1 mm2 = 10–6 m2 ℓ = 1 mm = 10–3 m Y = 2 × 1010 N/m2 [ (workdone) / (volume)] = (1/2) × stress × strain = (1/2) ∙ Y ∙ (strain)2 (1) Now strain = (ℓ/L) = (10–3 / 0.5) = (10–2 / 5) Volume = A ∙ L = 10–6 × 0.5 = 5 × 10–7 m3 ∴ from (1) Workdone = (1/2) × 2 × 1010 × (10–2 / 5)2 × 5 × 10–7 fitbit recording too many stepsWebIf the work done in stretching a wire by 1 mm is 2J, then work necessary for stretching another wire of same material but with double radius of corss-section and half the length … can gardevoir learn attractWeb5 dec. 2024 · Calculate the work done in stretching steel wire of length 2m and of cross sectional area 0.0225 mm², when a load of 100 N is applied slowly to its free end. ( Young's modulus of steel = 20 x 10¹⁰ N / … fitbit recover account